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Circle’s Circumference And Area Of Sectors And Segments

Last updated on Jul 14, 2026
Author Rupinder Kaur

Circle

We can calculate area and perimeter (circumference) of a circle because it is a closed curve by the following formulas.

Circumference of circle

Circumference is the length of the boundary of the circle. Its units are same as that of length i.e meter, centimeter, millimeter etc.

The circumference of a circle with radius r can be calculated by multiplying diameter with the constant π.

As diameter of a circle is double of its radius. So, the formula used to find circumference is 2 π r.

where, r is radius of circle and π is a constant value.

The value of π = 22 7

or = 3.14

Circumference of circle

In the figure below the boundary of the circle is marked with "Circumference".

Circumference of circle
Formula

Circumference of circle = 2 π r

Area of circle

Area of circle is a measure of space of the surface of circle. Its units are same as that of area i.e meter2, centimeter2, millimeter2 etc.

In the figure below the shaded part inside the circle denotes the area of the circle.

Area of circle
Area of circle

The area of a circle with radius r can be calculated using the formula π r2. where, π is the constant value and r is radius of the circle.

Formula

Area of circle = π r2

Semi circle

Circumference

Semi circle is a half part of a circle divided into two equal parts by the diameter. The circumference of semi circle is the length of its curved path. This length becomes equal to the half of circumference of the circle.

Circumference of semi circle
Circumference of semi circle

The circumference of a semi circle with radius r can be calculated by doing half of the Circumference of circle 2 π r 2 , which becomes π r.

Formula

Circumference of semi circle = π r

Perimeter

Perimeter of semi circle is the total length of it boundary, which is equal to sum of its circumference and diameter.

Formula

Perimeter of semi circle = π r + D, where r is radius of semi circle and D is its diameter

Area

The Area of semi circle is half of the area of the circle.

Area of semi circle
Area of semi circle

The area of a semi circle with radius r can be calculated by doing half of the area of circle as π r 2 2

Formula

Area of semi circle = π r 2 2

Area of minor sector

Area of sector of a circle is the region of the circle that is bounded by an arc and two radii of the circle.

In the figure below the shaded part inside the circle denotes the area of the sector of the circle, formed by two radii which make an angle θ at the centre of circle (called as central angle) and the opposite minor arc.

Area of sector is always assumed as the area of minor sector area if "minor" is not mentioned.

Minor sector always has central angle of measure less than 180°.
Area of minor sector of circle
Area of minor sector of circle

In degrees

The area of circle π r2 covers the full circle. This whole area of circle is covered by a sector whose two radii coincides each other and make the central angle θ = 360°.

Central angle of 360° covers the area of circle = π r2

Central angle of 1° covers the area of circle = π r 2 360 o

Central angle of θ covers the area of circle = π r 2 360 o × θ

∴ area of sector of circle with central angle θ = π r 2 360 o × θ

= θ 360 × π r 2

Area formula of minor sector in degrees

Area of minor sector of circle in degrees = θ 360 × π r 2

where θ is the central angle in degrees.

In radians

360° in radians can be written as 2 π radians

∴ the area of sector in radians = θ × π r 2

Area formula of minor sector in radians

Area of minor sector of circle in radians = θ × π r 2

where θ is the central angle in radians.

With length of arc

The whole area of circle is covered by an arc whose length is equal to the circumference of the circle, which is 2 π r.

∴ Length of arc 2 π r covers the area of circle = π r2

Length of arc 1 covers the area of circle = π r 2 2 π r

Length of arc l covers the area of circle = π r 2 2 π r × l = rl 2

∴ area of sector of circle with arc of length l = rl 2

Area formula of minor sector with length of arc

Area of minor sector of circle when length of arc is given = r l 2

where r is radius and l is length of arc.

The minor sectors in the circle have their names depending upon the size of the central angle as listed in the following table.

Table of name of sectors and the central angle
Central angle of sector Name of sector
90° Quadrants
60° Sextants
45° Octants

Area of major sector

Area of major sector is the area left other than the area of minor sector of circle.

The figure below shows the area of major sector with the shaded part formed by two radii which make a central angle of θ in minor sector and the opposite major arc.

Area of major sector of circle
Area of major sector of circle

It is calculated by subtracting the area of minor sector from the total area of the circle.

Area of major sector = area of circle - area of minor sector
Formula

Area of major sector = ( 360 - θ ) 360 × π r2

where θ is the central angle in minor sector in degrees.

Major sector always has central angle of measure greater than 180°.

Area of minor segment

Area of minor segment is the region enclosed between a minor arc and the chord. The figure below shows the area of minor segment with the shaded part.

Minor segment of circle
Area of minor segment of circle
Area of minor segment of circle
Area of minor segment of circle

In the above diagram, the shaded part below the chord AB is the area of the minor segment.

OA and OB are the two radii of length r. θ is the central angle.

So, Area of minor segment = area of minor sector - area of ΔAOB

Area of minor sector = θ 360 o × π r 2

To calculate the area of ΔAOB, follow the steps below.

Area of ΔAOB = 1 2 × AB × OL

In ΔAOL AL OA = Sin θ 2

AL r = Sin θ 2

AL = r Sin θ 2

AB = 2 × AL

AB = 2 × r Sin θ 2 = 2 r Sin θ 2

Also, OL OB = Cos θ 2

OL r = Cos θ 2

OL = r Cos θ 2

∴ Area of ΔAOB = 1 2 × 2 × r Sin θ 2 × r Cos θ 2

= r 2 Sin θ 2 × Cos θ 2

Again, Area of minor segment = area of minor sector - area of ΔAOB

= θ 360 o × π r 2 - r 2 Sin θ 2 × Cos θ 2

= r2 ( θ 360 o × π - Sin θ 2 Cos θ 2 )

Formula

Area of minor segment = r2 ( θ 360 o × π - Sin θ 2 Cos θ 2 )

Area of major segment

Area of major segment is the region enclosed between a major arc and the chord. The figure below shows the area of major segment with the shaded part.

Area of major segment of circle
Area of major segment of circle

Area of major segment = π r2 - Area of minor segment

= π r2 - r2 ( θ 360 o × π - Sin θ 2 Cos θ 2 )

= π r2 - θ 360 o × π r 2 - r 2 Sin θ 2 Cos θ 2

= r2 ( π - θ 360 o × π - Sin θ 2 Cos θ 2 )

= r2 [ π ( 1 - θ 360 o ) - Sin θ 2 Cos θ 2 ]

= r2 [ π ( 360 o - θ 360 o ) - Sin θ 2 Cos θ 2 ]

Formula

Area of major segment = π r2 - Area of minor segment

or = r2 [ π ( 360 o - θ 360 o ) - Sin θ 2 Cos θ 2 ]

Length of arc

The length of arc is the distance between two points on the boundary of a circle.

Length of arc of circle
Length of arc of circle
Formula

Length of arc (in degrees) = θ 360 o × 2 π r

Length of arc (in radians) = θ r

Formulas list of areas & perimeters

Table of formulas list of circle
Name Formula
Area π r2
Circumference 2 π r
Table of formulas list of semi circle
Name Formula
Area π r 2 2
Circumference π r
Perimeter π r + D
Table of formulas list of sectors
Name Formula
Area of minor sector (in degrees) θ 360 × π r 2
Area of minor sector (in radians) θ × π r 2
Area of minor sector (with length of arc) r l 2
Area of major sector ( 360 - θ ) 360 × π r2
Table of formulas list of segments
Name Formula
Area of minor segment r2 ( θ 360 o × π - Sin θ 2 Cos θ 2 )
Area of major segment π r2 - Area of minor segment

or r2 [ π ( 360 o - θ 360 o ) - Sin θ 2 Cos θ 2 ]

Frequently Asked Questions

What is π and how it is calculated?

π is a value that never changes. If calculated, it always remains constant which is equal to 3.14. It is calculated by dividing the circumference of the circle to the diameter of the circle. It is a ratio of circumference and diameter of a circle.

This constant value is denoted by π and read as pi. π = Circumference Diameter

Solved Examples

Calculate circumference of circle whose radius is 5cm.

Radius of circle = 5cm

Circumference of circle = 2 π r

= 2 π × 5

= 2 × 3.14 × 5

= 31.4 cm


Calculate area of circle whose radius is 10cm.

Radius of circle = 10cm

Area of circle = π r2

= π × 102

= 3.14 × 100

= 314 cm2


Calculate sector area of circle with radius of 3 cm and angle of 40°.

An hour hand moved from 3 to 6

Given, sector is OACB,

radius OA = 3 cm,

and θ = 40°

Because, central angle is 40° which is less than 180°, so it will create a minor sector only.

Area of minor sector = θ 360 o × π r 2

= 40 360 × 22 7 × 3 × 3

= 40 360 × 22 7 × 9

= 40 40 × 22 7

= 22 7 cm 2


Find the area of major sector circle with radius of 4 cm and angle of 60°.

An hour hand moved from 3 to 6

Given, sector is OAPB,

radius OA = 4 cm,

and θ = 60°

Area of major sector = ( 360 - θ ) 360 × π r 2

= ( 360 - 60 ) 360 × 22 7 × 4 2

= 300 360 × 22 7 × 16

= 30 36 × 22 7 × 16

= 5 6 × 22 7 × 16

= 5 3 × 22 7 × 8

= 880 21 cm 2


Find the area of segment of circle whose radius is 14 cm and central angle is 60°.

An hour hand moved from 3 to 6

Given, sector is OAPB,

radius of circle = 14 cm,

θ = 60°

Area of minor segment = r 2 [ θ 360 o × π - Sin θ 2 Cos θ 2 ]

= 14 2 [ 60 360 × 22 7 - Sin 60 o 2 Cos 60 o 2 ]

= 196 [ 1 6 × 22 7 - Sin 30 o Cos 30 o ]

= 196 [ 1 3 × 11 7 - 1 2 × 3 2 ]

= 196 [ 11 21 - 3 4 ]

= 196 [ 44 - 21 3 84 ]

= 7 [ 44 - 21 3 3 ] cm 2


A sector is cut from the circle of radius 20 cm and central angle is 100°. Find length of the arc.

An hour hand moved from 3 to 6

Radius = 20 cm,

θ = 100°

Length of arc = θ 360 × 2 π r

= 100 360 × 2 × 22 7 × 20

= 4000 360 × 22 7

= 400 36 × 22 7

= 100 9 × 22 7

= 2200 63 cm

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