Pythagoras Theorem

Level Secondary

Chapter Contents

Theorem

In a right angled triangle, the square of hypotenuse is equal to the sum of the square of other two sides.

Right angle $\triangle ABC$

$Right angle $\triangle ABC$$

In the above right angle $\triangle ABC$, p is perpendicular, b is base and h is hypotenuse.

$h^2 = b^2 + p^2$

or $h = \sqrt{b^2 + p^2}$

Example

Find the length of hypotenuse of right angle $\triangle ABC$, where length of base =3cm and length of perpendicular = 9cm.

Solution:

In $\triangle ABC$

b=3cm

p=4cm

$\because $, $\triangle ABC$ is a right angle triangle (given)

$\therefore $ by applying Pythagoras theorem

$h = \sqrt{b^2 + p^2}$

$h = \sqrt{3^2 + 4^2}$

$h = \sqrt{9 + 16}$

$h = \sqrt{25}$

$\therefore $ $h = 5cm$

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Last updated on: 17-04-2023