One of the most interesting number pattern in mathematics is Pascal’s triangle. This pattern is developed by a famous french mathematician and philosopher,
Blaise Pascal.
To build the Pascal’s triangle start with 1 at top, then continue placing numbers below it in a triangular pattern.
The two side edges always have 1s placed on them.
Each number in Pascal’s triangle is the sum of two numbers just around it in the above row.
In above figure, which is a Pascal’s triangle,
There are only 1s numbers placed on the two edges.
In \(3^{rd}\) row, 2 is sum of 1 and 1 placed in \(2^nd\) row.
In \(4^{th}\) row, 3 is sum 1 and 2 placed in \(3^rd\) row.
In \(5^{th}\) row, 4 is sum 1 and 3 and 6 is sum of 3 and 3 placed in \(4^th\) row.
In \(6^{th}\) row, 6 is sum 1 and 5, 15 is sum of 5 and 10 and 20 is sum of 10 and 10 placed in \(5^th\) row.
In \(7^{th}\) row, 7 is sum 1 and 6, 21 is sum of 6 and 15 and 35 is sum of 20 and 15 placed in \(6^th\) row.
The above figure, shows an interesting pattern formed with the numbers those are placed diagonally.
The first diagonal is just only 1s.
The second diagonal has counting numbers i.e. 1, 2, 3, 4, 5, 6, 7 etc., which is a sequence of integers.
The third diagonal of Pascal’s triangle has sequence of numbers 1, 3, 6, 10, 15, 21 etc. This series of numbers is also called triangular numbers.
The fourth diagonal is also an interesting sequence of numbers 1, 4, 10, 20, 35 etc., which are called as tetrahedral numbers.
The sum of numbers on rows of Pascal’s triangle makes up the power of 2.
Let’s understand it from the above figure.
\(1^{st}\) row: 1 = 1 = 11
\(2^{nd}\) row: 1 + 1 = 2 = 21
\(3^{rd}\) row: 1 + 2 + 1 = 4 = 22
\(4^{th}\) row: 1 + 3 + 3 + 1 = 8 = 23
\(5^{th}\) row: 1 + 4 + 6 + 4 + 1 = 16 = 24
\(6^{th}\) row: 1 + 5 + 10 + 10 + 5 + 1 = 32 = 25
\(7^{th}\) row: 1 + 6 + 15 + 20 + 15 + 6 + 1 = 64 = 26
\(8^{th}\) row: 1 + 7 + 21 + 35 + 35 + 21 + 7 + 1 = 128 = 27